Note: this process can be
applied to any voltage light set - just substitute the new voltage into the
equations, eg Vdc = 12V instead of 24Vdc. Note: the Vac is only used for rough calculation and then the transformer is bought to suit the AC supply voltage.
If you have any questions, please email me with all the details so I can help you.
Assumptions
We have a light string with
30 blue LEDs and it has a separate bridge rectifier. Also it has an extension
socket. See Step 1 diagram.
I've got a 120V/ 24VAC 10W
transformer from old light bulb set.
Design Process
First do a rough calculation
to determine a satisfactory series parallel configuration then do a final
design.
Step 1
Rough Calculations
A blue LED has a typical
voltage drop of 3.4V.
So 30 blue LEDs have a total
voltage drop of 30*3.4= 102V.
Supply voltage is 120VAC,
bridge rectified Vdc = Vac * 0.9 = 120 * .9= 108V
Since total LED voltage of
102V is less than Vdc of 108V, we can expect all LEDs to be series connected as
shown in Step 1 diagram. A careful inspection of wiring between LEDs confirms
this is correct, ie 28 LEDs have only 2 wires connected; each end LED has 3
wires (2 supply + 1 series) as shown. (Note if the total LED voltage was greater than
Vdc, we can expect LEDs to be series parallel connected.)
Determine Transformer
size
The total wattage for lights
= no. lights * V/ LED * current
We'll chose 20mA (0.02A) as
current value.So wattage = 30 * 3.4 * .02 = 2.04W .... transformer is big enough.
I measured the transformer
output to be 27.6V AC at no load with 120V AC input voltage. The light's wattage is
2.04W and it's about 1/5 of transformer's 10W rating. So you could connect an
additional 3 identical light sets to the transformer through the extension
socket.
Determine Light
configuration
Calculate maximum no. series blue LEDs using my transformer:
= 27.6 *.9 / 3.4 = 7.3 LEDs
(this gives good
brightness). This number shows we need parallel lots of series groups.
It's best to have the same
number of LEDs (and colour mixture) in a series group so the brightness is
even across the string.
So we could chose: 5
parallel lots of 6 series blue LEDs, or
6 parallel lots of 5
series blue LEDs, etc.
Final Design Calculations
Total LED voltage per series
group = 5 * 3.4 = 17.0V
The supply voltage can
vary between 105% to 90% of nominal. We'll ignore this factor because its affect is small.
The Vdc output from bridge
rectifier = 27.6 * .9 = 24.8V
We need to calculate a
current limiting resistor. To calculate the voltage
across the resistor, subtract the LED series voltage from the supply voltage:
V resistor = Vdc output –
LED series voltage = 24.8 -17.0= 7.8V
Now we want .02A flowing
through the LEDs which also flows through the resistor (it’s a series circuit - see Diagram 4).
So use Ohm’s Law to calculate the resistance value:
R = voltage/ current or V/I
R = 7.8/ .020 = 390 Ohms;
this is a standard value!
Resistor power rating: P =
V*I = 7.8 * 0.02 = .156W; we could use a 1/4W size but it will get too hot.
So use a resistor about 3 times the wattage to keep it cool, say a 1/2W size.
This will only cost an extra 10c!
Final Design Parameters:
6 parallel lots of (5 series
blue LEDs plus resistor 390 Ohms 1/2W). This is shown below as an electrical diagram.
NEXT >> Step 2 Cutting up your lights!
In this section we'll convert a 120VAC set of LED lights to operate off 24VDC which could be a transformer and rectifier, or a 12V car battery and ... ledlights12v.blogspot.com
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